What are the sine cosine and tangent of theta=7pi/4 radians

Answer:see explanationStep-by-step explanation:[tex]\frac{7\pi }{4}[/tex] is in the fourth quadrantWhere sin and tan are < 0 , cos > 0The related acute angle is 2π - [tex]\frac{7\pi }{4}[/tex] = [tex]\frac{\pi }{4}[/tex]Hencesin([[tex]\frac{7\pi }{4}[/tex] ) = - sin([tex]\frac{\pi }{4}[/tex]) = - [tex]\frac{1}{\sqrt{2} }[/tex] = - [tex]\frac{\sqrt{2} }{2}[/tex]cos([tex]\frac{7\pi }{4}[/tex]) = cos([tex]\frac{\pi }{4}[/tex]) =  [tex]\frac{\sqrt{2} }{2}[/tex]tan([tex]\frac{7\pi }{4}[/tex]= - tan([tex]\frac{\pi }{4}[/tex] = - 1