The equation of line ab is y = 5x + 1. write an equation of a line parallel to line ab in slope-intercept form that contains point (4, 5). y = 5x β 15 y = 5x + 15 y = x + y = x β
Accepted Solution
A:
METHOD 1: The equation of line parallel to ax+by=c is, ax+by=k Similarly,in this case equation of line parallel to the st line y=5x+1 (i.e, 5x-y=-1) is given by, 5x-y=k......(i) As equation (i) is the line containing (4,5), k=5Γ4-5=15 Hence equation (i) becomes, 5x-y=15 y=5x-15β‘required equation (ANS)
METHOD 2:
As slope of AB is 5, the slope of line parallel to AB should also be 5. Thus, the equation of st line parallel to AB (with slope 5) & passing through (4,5) is: m=(y-y1)/(x-x1) 5=(y-5)/(x-4) 5x-20=y-5 y=5x-15β‘ required eqn